1.45x^2=29x

Solution for 1.45x^2=29x equation:

1.45x^2=29x

We move all terms to the left:

1.45x^2-(29x)=0

a = 1.45; b = -29; c = 0;
Δ = b2-4ac
Δ = -292-4·1.45·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-29}{2*1.45}=\frac{0}{2.9}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+29}{2*1.45}=\frac{58}{2.9}
=20
$